Re: Testing AjaxSubmitLink#onSubmit() with WicketTester @L

[Alec Swan]

I unsuccessfully tried several different ways to invoke the AjaxSubmitLink
from my test method.

   1. formTester.submit("submitButton") does not call
   AjaxSubmitLink#onSubmit(AjaxRequestTarget target, Form form)
   2. formTester.submitLink("submitButton", false) fails with
   *org.apache.wicket.WicketRuntimeException: Link
   panel:referralForm:submitButtonis an AjaxSubmitLink and will not be invoked
   when AJAX (javascript) is disabled.*
   3. tester.clickLink("referralForm:submitButton, true) does not call
   AjaxSubmitLink#onSubmit(AjaxRequestTarget target, Form form)
   4. EnhancedWicketTester.clickAjaxLink("referralForm:submitButton") fails
   with
   *junit.framework.AssertionFailedError: component
   'ReferralPanel$ReferralForm$2' is not type:Link*
   This makes sense because AjaxSubmitLink class is not a subclass of Link.

So, how do I test AjaxSubmitLink#onSubmit(AjaxRequestTarget target, Form
form) method?

Thanks,

Alec

@L

On Sun, Dec 27, 2009 at 9:44 AM, Alec Swan <alecs...@gmail.com> wrote:

> I have a page with a form and AjaxSubmitLink in the form.
>
> I call WicketTester#clickLink(pathToLink, true) to test the code in
> AjaxSubmitLink#onSubmit(). The call returns with no errors, but
> AjaxSubmitLink#onSubmit() is never called.
>
> Here is a code sample:
>
>         tester.startPanel(MyPanel.class);
>         final FormTester formTester = tester.newFormTester(FORM_PATH);
>
>         // Test: Submit form with valid inputs
>         formTester.setValue("company", "company");
>         formTester.setValue("phone", "phone");
>         *tester.clickLink(SUBMIT_LINK_PATH, true);*
>
> Thanks,
>
> Alec
>
>
>
>
>