Take a look at the AjaxButton if you need an asynchronous submit, and
implement your onError handlers with:
target.addComponent( myFeedbackPanelThatMabyWillShowSomeMessageIfGetUpdated
);
On Tue, Jan 26, 2010 at 4:34 PM, Anna Simbirtsev <asimbirt...@gmail.com>wrote:
> I have, but maybe its incorrect.
>
> <div wicket:id="popup_feedback" id="popup_feedback"></div>
>
> contact_form.add(new FeedbackPanel("popup_feedback", new
> ContainerFeedbackMessageFilter(contact_form) ));
>
> On Tue, Jan 26, 2010 at 1:32 PM, Pedro Santos <pedros...@gmail.com> wrote:
>
> > Do you have an feedback panel on the model? If don't, add one and see if
> > your form don't pass in some validation like on required field.
> >
> > On Tue, Jan 26, 2010 at 4:07 PM, Anna Simbirtsev <asimbirt...@gmail.com
> > >wrote:
> >
> > > Hello,
> > >
> > > I have a modal window that is used to create a contact and needs to
> > submit
> > > data to the server once submit button is called.
> > >
> > > The submit button is defined as follows:
> > >
> > > <button wicket:id="contact_submitbutton" type="submit">SUBMIT</button>
> > >
> > >
> > > contact_form.add(new Button("contact_submitbutton").add(new
> > > AjaxFormSubmitBehavior(contact_form, "onclick") {
> > >
> > > private static final long serialVersionUID =
> > > 4192112499051970470L;
> > >
> > > protected void onSubmit(AjaxRequestTarget target)
> > > {
> > > System.out.println("Inside contact link's onSubmit is
> > > called" );
> > >
> > > }
> > >
> > > @Override
> > > protected void onError(AjaxRequestTarget target)
> > > {
> > > }
> > > }));
> > >
> > >
> > > But nothing happens when I click on the button.
> > >
> > > Thanks,
> > >
> > > Anna
> > >
> >
> >
> >
> > --
> > Pedro Henrique Oliveira dos Santos
> >
>
>
>
> --
> Anna Simbirtsev
> (416) 729-7331
>
--
Pedro Henrique Oliveira dos Santos
