ajax link does not submit form.. use submitlink or ajaxbutton
**
Martin
2010/3/27 chinedu efoagui <chinedub...@gmail.com>:
> Hello all,
> I have this dropdown that shows up a list of employee see code below
>
> <code>
> public EmployeeDropDownChoice(String id,IModel model,IModel model2){
>
> super(id,model,model2);
> final ChoiceRenderer renderer = new ChoiceRenderer("fullname", "id");
>
> setChoiceRenderer(renderer);
> List<PersonnelrecordsEmployee> emps=Collections.EMPTY_LIST;
> try {
> emps = dao.getPersonnelrecordsEmployeeList();
> } catch (GenericBusinessException ex) {
>
> Logger.getLogger(EmployeeDropDownChoice.class.getName()).log(Level.SEVERE,
> null, ex);
> }
> setChoices(emps);
> }
> </code>
>
> Now in the panel/form when i call it since the form uses a
> CompoundPropertyModel I declare the dropdown like this
> final EmployeeDropDownChoice forwardofficer=new
> EmployeeDropDownChoice("forwardofficer",new Model(),new Model(""));
> to avoid compoundpropertymodel issues is the EmployeeDropdown is
> not a member of the backing object of the form.
> NOw this is the problem
>
> when i try to get the defaultmodelobject from the Employeedropdown it
> give me null.
> How do i retrieve the selected choice from the Employeedropdown??
> <code>
> final AjaxFallbackLink forwardbutton=new AjaxFallbackLink("forwardbutton") {
> �...@override
> public void onClick(AjaxRequestTarget art) {
>
> final LeaveappEmpleaveApprovalOfficers
> leaveappOfficerss=new LeaveappEmpleaveApprovalOfficers();
> leaveappOfficerss.setEmpleaveIdLeaveappEmpleave(selected);
> //PersonnelrecordsEmployee
> zaemployeee=(PersonnelrecordsEmployee)forwardofficer.getDefaultModelObject();
> //System.out.println("personnel
> id:"+zaemployeee.getFullname() );
> System.out.println("personnel
> id:"+forwardofficer.getDefaultModelObject());
> try {
>
> dao.addLeaveappEmpleaveApprovalOfficers(leaveappOfficerss);
> </code>
>
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