WicketAjaxDebug.original = WicketAjaxDebug.logError;
WicketAjaxDebug.logError =
function(msg){WicketAjaxDebug.original(msg);console.log(msg);};On Tue, Mar 30, 2010 at 7:11 AM, Martin U <ufer.mar...@googlemail.com>wrote: > Hi Folks, > > > have everyone of you any experience in catching the wicket-ajax and > js-errors with the Firebug? > > Easily we just need to overwrite WicketAjaxDebug.logError... but how? > > > Thanks for any advice! > -- Pedro Henrique Oliveira dos Santos
