Thanks for replying and sorry about typos. Here is the real code
<div wicket:id="seeAllWrapper"><a href="#" wicket:id="seeAll"> <img
src="images/al_faqarrow1_gen.gif" style="vertical-align:middle" border="0"/>See
All </a></div>
<div wicket:id="seeRecentWrapper"><a href="#" wicket:id="seeRecent"><img
src="images/al_faqarrow1_gen.gif" style="vertical-align:middle" border="0"/>
View Most Recent </a></div>
seeAll and seeRecent links visibility is set to default , which I assume is
true.
Initialy seeRecentWrapper visibility is set to false and seeAllWrapper
visibility is set to true.
On click on seeAll Ajax link I am setting seeRecentWrapper.setVisible(true) and
seeAllWrapper.setVisble(false)
On click on seeRecent Ajax link I am setting seeRecentWrapper.setVisible(false)
and seeAllWrapper.setVisble(true)
If setting parent component visibility does not affect its child visibility So
not sure why links doesn't show up. Any idea?
-----Original Message-----
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, June 01, 2010 10:36 AM
To: users@wicket.apache.org
Subject: Re: How to make visible all child of WebMarkupContainer
On Tue, Jun 1, 2010 at 12:25 PM, <gurpreet.si...@wellsfargo.com> wrote:
> Hi All,
>
>
> I am getting strange problem. Setting WebMarkupContainer.setVisible(true)
> is not making all its child visible via Ajax Link.
>
> My Html code looks like this
>
> <div wickit:id="wrapper1"><img><a wicked:id="ajaxlink1">Show All</a></div>
> <div wickit:id="wrapper2"><img><a wicked:id="ajaxlink2">Show
> Recent</a></div>
>
> I need to show one of those links at a time. But somehow setting
> setVisible(true) is not working , but setVisible(false) works
>
Is that really your code? There are multiple typos that would stop stuff
from working. Please paste real code.
Anyway, if you have setVisible(false) on any children, then calling
setVisible(true) on the parent will not make the children also visible.
However, if the parent (webmarkupcontainer) were not visible, then obviously
the children would not be visible, even though their individual isVisible()
methods would return true.
--
Jeremy Thomerson
http://www.wickettraining.com
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