arunarapole wrote: > > Thank you for replay i am very glad you have sent me the sample code thank > you so much > > My problem is i have to handle SQLException and only message to be > display > in hidden field same webpage > > do u have any idea regarding this > > Aruna > >
It depends. Is your exception thrown in an ajax call or a form submit? In your WebRequestCycle.onRuntimeException you have two parameters: page on which exception was thrown and which exception was thrown. If your runtime exception was SQLException then you can access any element on your page and set any value to it. Next you can update an element on page if it's AJAX or show this page again by returning updated page. You can get your ajax target this way: (AjaxRequestTarget)RequestCycle.get().getRequestTarget(). -- View this message in context: http://apache-wicket.1842946.n4.nabble.com/EXception-handling-in-Wicket-tp2340439p2399426.html Sent from the Wicket - User mailing list archive at Nabble.com. --------------------------------------------------------------------- To unsubscribe, e-mail: [email protected] For additional commands, e-mail: [email protected]
