What about redirectToInterceptPage(new FormPage());
and in FormPage onSubmit: if (!continueToOriginalDestination()) { setResponsePage(Application.get().getHomePage()); } Regards, Bernard On Wed, 1 Sep 2010 20:30:20 -0700, you wrote: >do not pass the page, pass the page reference, see page#getpagereference() > >-igor > >On Wed, Sep 1, 2010 at 6:21 PM, Chris Merrill <ch...@webperformance.com> wrote: >> On 9/1/2010 7:26 PM, Chris Colman wrote: >>> I have a form/page that can be invoked from different pages so I can't >>> easily specify which page should be returned to after submit. >> >> When I needed to do this, I passed the original page into the page >> constructor >> where it was passed to the onSubmit() handler. Then the onSubmit() method >> set it as the return page: >> getRequestCycle().setResponsePage(_return_to_page); >> >> >> -- >> ------------------------------------------------------------------------ - >> Chris Merrill | Web Performance, Inc. >> ch...@webperformance.com | http://webperformance.com >> 919-433-1762 | 919-845-7601 >> >> Web Performance: Website Load Testing Software & Services >> ------------------------------------------------------------------------ - >> >> --------------------------------------------------------------------- >> To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org >> For additional commands, e-mail: users-h...@wicket.apache.org >> >> > >--------------------------------------------------------------------- >To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org >For additional commands, e-mail: users-h...@wicket.apache.org --------------------------------------------------------------------- To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org