If you have full control over the contents of your dialog you could try to
1- create the interface to mark your dialog:
public interface IAjaxSubmitAware {
void onSubmit(AjaxRequestTarget target);
}
2- create your own link, buttons, etc as in
public abstract class MyAjaxSubmitLink extends AjaxSubmitLink {
private static final long serialVersionUID = 1L;
/**
* @param id
*/
public MyAjaxSubmitLink(String id) {
super(id);
}
/**
* @param id
* @param form
*/
public MyAjaxSubmitLink(String id, Form<?> form) {
super(id, form);
}
@Override
protected final void onSubmit(AjaxRequestTarget target, Form<?> form) {
IAjaxSubmitAware submitAware =
findParent(IAjaxSubmitAware.class);
if(submitAware != null) {
submitAware.onSubmit(target);
}
doOnSubmit(target, form);
}
protected abstract void doOnSubmit(AjaxRequestTarget target, Form<?>
form);
}
Ernesto
On Tue, Dec 14, 2010 at 9:16 PM, guydog28 <g...@guydo.com> wrote:
>
> Anyone? Abstract: I have extended WiQuery Dialog with our own custom
> dialog. I want the MyDialog to know if any child components are a Form,
> being submitted via AJAX (AjaxFormSubmitBehavior). I need access to the
> AjaxRequestTarget created by that ajax form submit so I can append
> javascript to it or add components. I'm really hoping someone has a
> suggestion that I missed. This is a major blocker for us right now.
> --
> View this message in context:
> http://apache-wicket.1842946.n4.nabble.com/How-to-listen-for-CHILD-ajax-form-submits-tp3086439p3087882.html
> Sent from the Users forum mailing list archive at Nabble.com.
>
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