On Mon, 30 Apr 2012 10:43:30 -0700 (PDT)
cmagnollay <[email protected]> wrote:
> if the map is called something like
>
> Map<Item, Integer> itemMap = new HashMap<Item, Integer>();
>
> Hmm, so I would instantiate the ListView like so?
> [...]
> Is this what you are implying somewhat? Thanks for the answer by the
> way, I had not considered just, for lack of a better term, "fooling"
> the listview into using my map elements.
Basically yes, though the propertymodel won't work like that. I'd do
something like this (pseudocode):
Map<Item,Integer> itemMap = ...;
IModel<List<Map.Entry<Item,Integer>>> mapListModel = new
LoadableDetachableModel() {
load() {
return new ArrayList<...>(itemMap.entrySet());
}
};
...new ListView<Map.Entry<...>>("id", mapListModel) {
populateItem(ListItem<Item,Integer li) {
...
}
}
Carl-Eric
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