Use ajax behavior, e.g., OnChangeAjaxBehavior
** Martin 2013/4/9 Bruno Moura <[email protected]>: > I need to update a model or object immediately after select > a DropDownChoice item. > > > Bellow is the code that I'm working: > > // > --------------------------------------------------------------------------------- > > add(new ListView[Company]("listCompanies", listData) { > > override protected def onBeforeRender() { > // > // ... > super.onBeforeRender() > } > > def populateItem(item: ListItem[Company]) = { > var company = item.getModelObject() > > //... > > val listClients: java.util.List[Client] = clientControler.listClients > > > item.add(new DropDownChoice("clientSelection", listClients,new > ChoiceRenderer[Client]("name"))) > > // > --------------------------------------------------------------------------------- > > In the Listview with properties of Company Object, > after choose a name property of the DropDownChoice, the model > Company would be updated with the Client Name selected. > > How can I achieve this? > > Thanks --------------------------------------------------------------------- To unsubscribe, e-mail: [email protected] For additional commands, e-mail: [email protected]
