Re: Resource that produces JSON and JQuery

[Andrea Del Bene]

On 06/10/2013 02:17 PM, Martin Grigorov wrote:
On Mon, Jun 10, 2013 at 3:11 PM, Andrea Del Bene <an.delb...@gmail.com>wrote:
The code is quite simple as it's basically a prototype. Java code:

@Override
     public void respond(Attributes attributes) {
         StringValue action = attributes.getParameters().**get(SEGMENT);
         attributes.getResponse().**write(calculateResponse(**action,
attributes));
     }

     private String calculateResponse(StringValue action, Attributes
attributes) {
         String response = "{{" +
                   "\"Herausgeber\": \"Xema\", " +
                   "\"Nummer\": \"1234-5678-9012-3456\"}}";

Why there are doubled '{' and '}' ?

Just the result of some bad ideas :)



         if(action.toString().equals(**SAVE)){
             IRequestParameters requestParameters = attributes.getRequest().
**getRequestParameters();
             response = requestParameters.**getParameterValue("**
teamCalendarJson").toString();
         }
         System.out.println(response);
         return response;
     }


As  you said the error could be a missing settings for content-type
header. Should I use "application/json"?

Yes.

I've tried with :

@Override
    public void respond(Attributes attributes) {
        StringValue action = attributes.getParameters().get(SEGMENT);
        WebResponse response = (WebResponse) attributes.getResponse();
        response.setContentType("application/json");
        response.write(calculateResponse(action, attributes));
    }

    private String calculateResponse(StringValue action, Attributes 
attributes) {
        String response = "{" +
                  "\"Herausgeber\": \"Xema\", " +
                  "\"Nummer\": \"1234-5678-9012-3456\"}";

        if(action.toString().equals(SAVE)){
            IRequestParameters requestParameters = 
attributes.getRequest().getRequestParameters();
            response = 
requestParameters.getParameterValue("teamCalendarJson").toString();
        }
        System.out.println(response);
        return response;
    }


but it still fail calling the error  function of getJSON.....


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