Hi Martin,
"throw RestartResponseException()" solves my problem.
Thank you.
Am 17.02.2015 um 14:50 schrieb Martin Grigorov:
> Hi,
>
> On Tue, Feb 17, 2015 at 2:07 PM, Karl-Heinz Golz <
> karl-heinz.g...@t-online.de> wrote:
>
>> hello,
>>
>> I'm faced with an error in following situation:
>> User opens a webpage (e.g. Page1), do some other things, comes back
>> after session time out and click some link (onClick-event) on the page.
>>
>> Then following exception is thrown:
>>
>> at
>>
>> org.apache.wicket.markup.MarkupStream.throwMarkupException(MarkupStream.java:526)
>> at
>> org.apache.wicket.MarkupContainer.renderNext(MarkupContainer.java:1438)
>> at
>> org.apache.wicket.MarkupContainer.renderAll(MarkupContainer.java:1557)
>> at
>>
>> org.apache.wicket.MarkupContainer.renderComponentTagBody(MarkupContainer.java:1532)
>> at
>>
>> org.apache.wicket.MarkupContainer.onComponentTagBody(MarkupContainer.java:1487)
>> at
>>
>> org.apache.wicket.markup.html.panel.DefaultMarkupSourcingStrategy.onComponentTagBody(DefaultMarkupSourcingStrategy.java:71)
>> . . .
>>
>> I try to avoid that like this:
>>
>> public class Page1 extends WebPage {
>>
>> public Page1() {
>> if (!UserSession.get().isUserSignedOn()) {
>> setResponsePage(new StartPage());
>>
> If you need to cancel the processing of the Page in its constructor you
> should use "throw RestartResponseException()".
>
>
>> return;
>> } else
>> normalHandling();
>> }
>> . . .
>> }
>>
>> I can see in log file that the if/else works as expected: the StartPage
>> is handled (but not shown).
>> But after that it tries to render Page1 again which throws the exception.
>>
>> What I finally want is: users should be led to the StartPage after
>> session time out in any case.
>>
>> Any recommendations how I should handle this are very welcome.
>>
>> Many thanks in advance
>> Karl-Heinz
>>
>>
>>
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