Hi,
try with an additional formTester:
tester.startPage(HomePage.class);
FormTester firstRequest = tester.newFormTester("form");
firstRequest.select("sites", 1);
tester.executeBehavior((AbstractAjaxBehavior)tester.getComponentFromLastRenderedPage("form:sites").getBehaviors().get(0));
tester.assertLabel("form:chosen","Bing");
FormTester secondRequest = tester.newFormTester("form");
secondRequest.submit("detailButton");
tester.assertInfoMessages("feedback","Bing");
Note that *when FormTester is created*, it pushes all values of a form
into the current request.
With your setup the value of the choice is missing in the second request.
Have fun
Sven
On 14.03.2017 10:16, Hans-Heinrich Braun wrote:
In my Application i have a DropDownSelect which changes a Label onUpdate
by AjaxFormComponentUpdatingBehaviorThen there is a Button which tries
access at the selected item. In the real Webapp it works fine but when i
test itwhen i click the Button the selected Item is null.What I am doing
wrong.
----------------------------------Here the HomePage:
public class HomePage extends WebPage {
private static final longserialVersionUID = 1L;
private static final List<String> SEARCH_ENGINES = Arrays.asList(new String[] { "Google",
"Bing", "Baidu" }); //
private String selected = "Google";
Model<String> model = new Model<String>() { public String
getObject() { return getSelected(); } };
private Label chosen=new Label("chosen", model);
public HomePage(final PageParameters parameters) { super(parameters);
FeedbackPanel feedback=new FeedbackPanel("feedback"); add(feedback);
feedback.setVisible(true); // other pages will set this to visible
feedback.setEscapeModelStrings(false); add(new
Label("version",getApplication().getFrameworkSettings().getVersion()));
DropDownChoice<String> listSites = new DropDownChoice<String>( "sites", new
PropertyModel<String>(this, "selected"), SEARCH_ENGINES);
Form<?> form = new Form<Void>("form");
final Button detailButton=new Button("detailButton") {
@Override public void onSubmit(){info(getSelected()); } };
detailButton.setOutputMarkupId(true);
chosen.setOutputMarkupId(true); listSites.add(new
AjaxFormComponentUpdatingBehavior("onchange") {
@Override protected void onUpdate(AjaxRequestTarget target)
{ target.add(chosen);
target.add(detailButton); } });
form.add(chosen); add(form); form.add(listSites); form.add(detailButton);
}
public String getSelected() { return selected; }
public void setSelected(String selected) { this.selected = selected; }}
----------------------------------------and here the Test :
public class TestHomePage{ private WicketTester tester;
@Before public void setUp() {
tester = new WicketTester(new WicketApplication()); }
@Test public void homepageRendersSuccessfully() {
tester.startPage(HomePage.class);
FormTester formTester = tester.newFormTester("form");
formTester.select("sites", 1); tester.executeBehavior((
AbstractAjaxBehavior)tester.getComponentFromLastRenderedPage("form:sites").getBehaviors().get(0));
tester.assertLabel("form:chosen","Bing");
formTester.submit("detailButton");
tester.assertInfoMessages("feedback","Bing");
}}
I am using wicket 6.26.0
---------------------------------------------------------------------
To unsubscribe, e-mail: [email protected]
For additional commands, e-mail: [email protected]
