I want to split a dato string like 2011.08.02 into year, month and days to calculate the age of a person. $year = 2011 $month = 08 $day = 02
$year =($date.replaceAll($'\d\d\d\d.','$1')) is not working. -- Volker Lapczynski http://RadWiki.net RadWiki.net -- View this message in context: http://xwiki.475771.n2.nabble.com/Velocity-replaceALL-split-dato-string-with-Regex-tp6841890p6841890.html Sent from the XWiki- Users mailing list archive at Nabble.com. _______________________________________________ users mailing list users@xwiki.org http://lists.xwiki.org/mailman/listinfo/users
