Indeed. It looks like Bill's message ended up opening up a Pandora's can of worms here... :-S
Marcus On Tue, 26 Mar 2002 00:41:15 Bruce Hebbard wrote: > >On Mon, 25 Mar 2002, Bill Hooper in USMA:19071 wrote: > > . . . >> The watt is also equal to a volt-ampere but that is not it's original >> definition. The watt is originally defined as a joule per second. Since the >> volt (V) is a joule per coulomb (J/C) and the coulomb (C) is defined as an >> ampere-second (A7s), it is easy to show that the volt-ampere equals the >> watt: >> 1 V7A = (1 J/C)7(1 A) = (1 J/A7s)7(1 A) = 1 J7s = 1 W > . . . > >That of course being the case, could someone please explain why serious >power equipment often uses VA (kVA, MVA, etc.) as distinct from W ? > >I recall recently seeing some small computer UPS (or some other >equipment) that was rated in both VA and W, with *different* numerical >values given for each. (Is this an RMS-vs-peak kind of thing?) This has >always perplexed me when I see VA used on utility transformers, etc. > >Bruce H. > > Is your boss reading your email? ....Probably Keep your messages private by using Lycos Mail. Sign up today at http://mail.lycos.com
