Hi Marcus:
  The people who can confirm the latest accepted or recently obtained 
results on Earth would be The National Geographic and Oceonography experts. 
The values I used were the latest available to me.
  Do let me have any NEW info, please!
Brij Bhushan Vij <[EMAIL PROTECTED]>

>From: "Ma Be" <[EMAIL PROTECTED]>
>Reply-To: [EMAIL PROTECTED]
>To: "U.S. Metric Association" <[EMAIL PROTECTED]>
>Subject: [USMA:21759] Re: Is the meter defined at sea level?
>Date: Fri, 16 Aug 2002 15:03:46 -0700
>
>On Sat, 17 Aug 2002 07:28:22
>  Pat Naughtin wrote:
> >Dear Marcus, Joe, and All,
> >
> >If I add Hayford's 'Equatorial circumference of the earth = 40 076.594 
>km'
> >and his 'Polar circumference of the earth = 39 941.028 km' and divide by 
>2,
> >does this give me the mean circumference of the Earth? In this case it 
>would
> >be 40 008.811 kilometres - or some 9 kilometres more than the original
> >(1792) figure.
> >
>Thanks for the info, Pat.  Now, I believe my question still has relevancy 
>since it's still unclear how one came up with the above values.  Did the 
>authors consider earth's relief, sea level values, disregarded relief 
>altogether, calculated at some arbitrary meridian?...  Until we know what 
>assumptions were used it's difficult to "check" the validity of the above 
>results.
>
>In any case, we could proceed to derive charts, cartography data, etc at 
>some arbitrary altitude (such as at my 560 m value).  This should not be 
>such a pain for the community since we could quote altitudes at RL instead 
>of SL (Reference Level and Sea Level, respectively).  No big deal, really.
>
> >BTW, Marcus, where did you get the number '560 m below sea level'?
> >
>Simple, I assumed that the "correct" value at sea level was 40003.52 km 
>(i.e. a value as quoted by another colleague here sometime ago).  Found a 
>radius of 6366.758 km.  Now subtract this value at a radius that would give 
>exacts 400000, i.e. 6366.198 and voil`, the value comes at 560 m below "sea 
>level" (if that's what was used to derive the "correct value").  If one 
>uses the nautical mile as referring to that (sea level), then the distance 
>becomes a convenient 500 m!  (well, ok... 510, 511...).
>
>The principle behind this calc could apply to any other value that is 
>deemed to be the "sea level" one.  Whatever the spherical difference in 
>altitude this would become the RL where 0.01 gr would be exacts 1 km.  
>Then, after doing this it would be a piece of cake to come up with GPS 
>charts and whatnot using the 100 gr angle system.  Current charts could 
>undergo very simple updates with just a footnote to it indicating what RL 
>is and all (except, of course, that these projections would refer to 
>decimal grids...).
>
>All airports in the world would use such RL as reference, and no longer the 
>SL.  There would be no potential for confusion, the nautical mile trash 
>would be history (and so would the hideous knot...) and presto!
>
>I hope this answered your question, Pat.
>
>Marcus
>
> >Cheers,
> >
> >Pat Naughtin CAMS
> >Geelong, Australia
> >
> >on 2002-08-17 01.18, Ma Be at [EMAIL PROTECTED] wrote:
> >
> >> Based on Joe's post below and other ones earlier shall we conclude that 
>we
> >> still do not have the answer to the above question (in the subject)?
> >>
> >> Again, I launch the question what would prevent us from defining a 
>specific
> >> diameter for purposes of navigation and cartography at some 560 m below 
>sea
> >> level and use the principle of "relative" altitudes and all (like we 
>already
> >> do with atmospheric pressure) to get rid of the nautical mile crap?
> >>
> >> Marcus
> >>
> >>>> J. F. Hayford reported to the International Geodetic and Geophysical 
>Union
> >>>> in 1926 that;
> >>>>         Equatorial circumference of the earth = 40 076.594 km,
> >>>>         Polar circumference of the earth = 39 941.028 km.
> >>>> My source does not state whether these figures are for sea level, as 
>seems
> >>>> likely, or if they take account of land and mountains.  However, the
> >>>> uncertainty in the radius of the earth can not exceed 50 metres.  
>That is,
> >>>> the uncertainty is only one part in 100 000.
> >>>>
> >>>> Joseph B.Reid...
> >>
> >>
> >> Is your boss reading your email? ....Probably
> >> Keep your messages private by using Lycos Mail.
> >> Sign up today at http://mail.lycos.com
> >>
> >
> >
>
>
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