Pierre, >From my limited knowledge of hydraulics, but with a degree in physics, I would suggest that the head should ideally be measured in pascals - after all what you are measuring is a pressure. In the case of a static head, you would use the equation P = density x height x gravity.
-----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Pierre Abbat Sent: 24 September 2008 18:14 To: U.S. Metric Association Subject: [USMA:41748] hydraulics in metric I'm taking hydraulics. The prof introduced the concept of head, which is energy divided by weight and has units of length. There are potential head (which is simply elevation), kinetic head, pressure head, and head loss (to friction or viscosity). When doing hydraulics in metric, do you use head, or do you compute in joules per kilogram, multiplying elevations by gravity? Pierre
