Bill & azll:

>.....having solved for y, one can now convert to decimal.
WHY, is this Metric....NOT decimal either? What a way to THINK METRIC!!!!!

No offences, please.

Brij Bhushan Vij 

(MJD 2455066)/1361+D-243W34-05 (G. Saturday, 2009 August 22H15:24 (decimal) EST

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From: [email protected]
To: [email protected]
Subject: [USMA:45689] RE: Decimal fractions or common fractions? (Metric or 
not?)
Date: Sat, 22 Aug 2009 11:02:25 -0700


Bill:
 
It's much simpler than that:
 
21y x 8 = 1
168y = 1
y = 1/168
 
Your second and third lines seem to be annotations, rather than part of the 
process. Also, no fractions are involved (above) other than in the solution, so 
the issue of decimal vs. fractions doesn't really come up. And, as you've 
indicated, having solved for y, one can now convert to decimal.
 
Bill 




Bill Potts
WFP Consulting
Roseville, CA
http://metric1.org [SI Navigator] 




From: [email protected] [mailto:[email protected]] On Behalf Of 
Bill Hooper
Sent: Saturday, August 22, 2009 10:38
To: U.S. Metric Association
Subject: [USMA:45688] Decimal fractions or common fractions? (Metric or not?)





On  Aug 19 , at 8:43 AM, Stephen Davis wrote:

I do believe that algebra sums are going to particularly difficult to work out 
using decimal fractions.
 
For instance a linear equation such as:
 
21y x 8 = 1
 
...is going to take some monumental working out using decimals. 
 
21y x 8 = 1
1 / 8 =1/8
1/8 / 21 = 1/168
y = 1/168



I see no difficulty with such an algebra problem. I would solve it just about 
like Stephan did, BUT ...


If it were part of a physics or other real world problem (rather than a "pure", 
numerical algebraic problem), I would add one final step. That step would be to 
divide out the ratio "1/168" to get: 0.00595


(Note that I immediately rounded off appropriately*. The long calculator 
calculation gives 0.005952381 ... etc.
I would never even bother to look at all those extra digits, but would just 
note and write the rounded value. That might not be wise for a pure algebra 
problem but it is certainly appropriate in the real world of "real numbers" 
with finite precision.)


Then, if it is a physics problem, the answer would (almost surely) be a 
measurable quantity and therefore would (almost surely) have units. If the 
quantity is a length, the units might be metres, for example. That would then 
allow me to simplify the number by changing from metres to millimetres (or even 
micrometres), thus: 0.00595 m = 5.95 mm (= 5950 µm).


In a purely algebraic problem, I would agree that one of the reasons for 
keeping the answer in ratio form (1/168) is the fact that, without units, there 
is no other way to express the answer in compact form. But real problems with 
real numbers are a different story.


So I agree that expressing such numbers in ratio form might be better than 
decimal form in some cases (algebraic). However, I continue to think that one 
should not teach common fractions and all the related arithmetic (adding them, 
dividing them, finding least common denominators, etc., etc.) early in 
students' education. That should wait until the students take an algebra course 
(usually high school, not elementary or middle school). In the elementary 
grades, students should be introduced ONLY to decimal fractions and decimal 
arithmetic (along with decimal based metric units of measure).



Bill Hooper
1810 mm tall
Fernandina Beach, Florida, USA


--------------------------------------------------

*The degree of rounding off would depend on the precision of the numerical 
values in the original problem (the "21", the "8" and the "1"). I have rounded 
the answer to three significant figures as is common for ordinary measures or 
where the exact degree of precision is unknown or unimportant.


==========================
   SImplification Begins With SI.
==========================

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