Parker Willey Jr. wrote, > Hi: > I was thinking the other day that some people think the word > "metric" is foreign. That could be one of the monkey wrenches > that keeps our country mostly using legacy measures. > So, since we use a decimal system of coinage, I propose that we > call the metric system of weights and measures simpl;y the > "Decimal" system of weights and measures. That is what it is! > In the United States, We can retain all the labels like liter, > kilometer, meter, millimeter, hectare. etc. > Now, think: The "Decimal" system of weights and measures. > Does that sound OK?

I think that would certainly help. I think another ____________ would be to adjust some of the comparatives. For instance, 1 gallon = 3.785411784 liters. Or, more comparatively, 1 quart = .946352946 liters. So, 10 L ≈ 10.566 qt. = 2.6415 gal.—which is easier to relate to liters?

`To get people comfortable with liters—say, in terms of gasoline—define`

`it as “$/qt”, rather than “$/gal.”, and “mi/qt”, rather than “mi/gal.”`

`(remember, this is just a transitional, getting people comfortable with`

`the conversion magnitudes phase! P=)`

Likewise, 1 fl oz. ≈ 29.5735 mL = 2.95735 cL—which more relates to fl oz.? The same approach applies to other designations: 1 m ≈ 3.28084 ft. = 39.37008 in.? or ≈ 1.09361 yd.? 1 oz. ≈ 28.35 g? or ≈ 2.835 dag? 29.86 inHg ≈ 758.4 mmHg ≈ 1011.2 hPa? or ≈ 75.84 cmHg ≈ 101.12 kPa? Another convoluted relationship is Fahrenheit and Celsius.

`The Fahrenheit freezing point (0 °F) is based on a specific salt water`

`mix (“brine”), thus the freezing point of “regular” fresh water is 32`

`°F, or 0 °C, while its boiling point is 212 °F, or 100 °C.`

If you subtract 32 from 212, you get 180. So, for the moment, letʼs define an “elementary” Fahrenheit, where °E = °F − 32, thus the boiling point of (fresh) water is 180 °E/100 °C.

`But wait, the Fahrenheit scale is sexagesimal degrees (“°”) in nature,`

`while Celsius is centesimal degrees, or gradiens (“ᵍ”): The freezing to`

`boiling point spread is 0 to 180° or 200ᵍ, so, based on °E, Celsius`

`should be double its value, or bicentesimal, °B = 2×°C, thus`

212 °F/100 °C should be 180 °E/200 °B (and, say, 77 °F/25 °C should be 45 °E/50 °B).

`I realize that is a bit much to swallow all at once, but the immediate`

`point here, is that a modified Fahrenheit expression should be used,`

`getting people comfortable with a lower, actual/undistorted (“+32”)`

`temperature.`

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