> I would like to pass command-line parameters to a wsgi script. Here's an
> example:
>
> app.py
> -------------------------------
> import argparse
>
> from flask import Flask
>
> parser = argparse.ArgumentParser()
>
> parser.add_argument(
> "--important_parameter",
> required=False,
> type=str,
> default='127.0.0.1')
>
> args = parser.parse_args()
>
> important_parameter = args.important_parameter
>
> app = Flask(__name__)
>
> @app.route('/')
> def index():
> return "index"
>
> if __name__ == '__main__':
> app.run()
> -------------------------------
>
> I can pass parameters to it by running
>
> $ python app.py --important_parameter 15
>
> I can call this script using uwsgi with the following:
>
> $ uwsgi --http 127.0.0.1:5000 --wsgi-file app.py --callable app
>
> Or with the following wsgi-file:
>
> app.ini
> -------------------------------
> [uwsgi]
> http = 127.0.0.1:5000
> wsgi-file = app.py
> callable = app
> -------------------------------
>
> Does uwsgi allow passing in that important_parameter somehow? I've
> searched online and found very terse solutions I didn't understand and
> couldn't make work. I've also considered passing the information through
> environment variables, but I would much prefer this method.
>
> Thank you very much for any help.
>
> Cheers,
> Thomas
> _______________________________________________
> uWSGI mailing list
> [email protected]
> http://lists.unbit.it/cgi-bin/mailman/listinfo/uwsgi
>
Hi, you can pass argument (the ones you read via sys.argv) with the
--pyargv option.
Otherwise just add your option to the uWSGI config file, and access them
with uwsgi.opt dictionary
--
Roberto De Ioris
http://unbit.com
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