Updates:
Cc: [email protected] [email protected]
Comment #1 on issue 4336 by [email protected]: Function literal constant
does not respect strict mode on first compile.
https://code.google.com/p/v8/issues/detail?id=4336
My theory is that the first time we parse the function literal, we haven't
parsed the 'use strict' string in the function body yet, so we assume
sloppy mode. The second time we parse the function literal, we know it's
strict from the scope info.
I don't know what effect that eval has though. Without the eval or the
brackets around f, this does not happen.
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