function Vector(a, b) {this.a = a; this.b = b;} var x = new Vector(1, 2);var y = new Vector(1, 3);var z = new Vector(1, 'a'); print( %HaveSameMap( x, y ) ); //trueprint( %HaveSameMap( x, z ) ); //false x.b;print( %HaveSameMap( x, z ) ); //trueprint( %HaveSameMap( y, z ) ); //false y.b;print( %HaveSameMap( y, z ) ); //true As we can see if the object property types are different they don't share their hidden class until we try to access the property in elder object which type is different. Can anyone give a clear explanation what is happening "behind the scenes". -- -- v8-dev mailing list [email protected] http://groups.google.com/group/v8-dev --- You received this message because you are subscribed to the Google Groups "v8-dev" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
