With that considered, when a function with a closure is called, if there 
are changes within the context are they altered in place or are new objects 
stored?

On Wednesday, June 20, 2018 at 11:58:07 AM UTC-7, Jakob Kummerow wrote:
>
> The "variable environment" of a closure is stored in a Context object on 
> the heap. HandleScope has nothing to do with it. Where variables are stored 
> depends on how they are used: variables local to a function are stored on 
> the stack, variables used by closures are stored in the Context.
>
> On Wed, Jun 20, 2018 at 8:56 AM <[email protected] <javascript:>> wrote:
>
>> I have a question about how V8 deals with closures. I understand that the 
>> variable environment becomes part of the function object, I dont know if 
>> this is re-written in place when the variables in it's [[scope]] change, 
>> and how these are dealt with in memory since the functions as they execute 
>> are pushed on and popped off the stack. Does the handler (HandleScope I 
>> believe has something to do with it) write a new definition with the new 
>> environment variables? Sorry if this is an unclear question, Im a newer 
>> developer and this is a curious behavior that I want to thoroughly 
>> understand. This may actually be a behavior that isnt unique to closures 
>> and perhaps all functions are treated the same in the heap, but Im truly 
>> curious and cant figure this out looking through the V8 documentation.
>>
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