Updates:
Status: WorkingAsIntended
Comment #1 on issue 1974 by [email protected]: Re: Issue 115790 in
chromium: JavaScript issue. Result different from expected
http://code.google.com/p/v8/issues/detail?id=1974
I think this is working as intended. Double values cannot be expected to be
100% accurate if their exact representation would require more mantissa
bits than are available. If you compute the (in theory) same double in two
different ways, like Math.pow() will do internally if you give it two
different sets of arguments, you cannot rely on the result to be exactly
the same: depending on the sequence of internally performed operations, the
rounding errors that both results necessarily contain can be a little
different.
Workarounds:
- use an arbitrary-precision Integer representation for your numbers
(JavaScript provides none, you'd have to implement it yourself)
- in this particular case, you could avoid the explicit calculation of the
products altogether, and represent each number as its sorted list of prime
factors instead
- or the easiest solution: account for slight rounding errors by changing
your counting condition to the following:
if (i == 0 || r[i]/r[i-1] > 1 + 1e-14) count++;
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