I don't understand why the following should not work
function parent()
{
}
parent.prototype.show = function()
{
print("parent showing\n");
}
var p = new parent();
p.show();
function child()
{
}
// This works
//child.prototype = p;
//var c = new child();
//c.show();
var c = new child();
c.prototype = p;
c.show();
--
Anthony Shipman Mamas don't let your babies
[EMAIL PROTECTED] grow up to be outsourced.
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