On Tue, Mar 31, 2009 at 6:56 PM, Louis Santillan <[email protected]> wrote:
> ...Because I made a typo. For clarity, the _superConstructor_.call()
> is referenced via SuperType._superConstructor_.call( this ). This
Aha. Okay, for clarity, here's what i've got now (which seems to work):
Object.prototype._extends_ = function( ChildClass, ParentClass )
{
if( 1 == arguments.length )
{
ParentClass = ChildClass;
ChildClass = this;
}
function TempClass() {}
TempClass.prototype = ParentClass.prototype;
ChildClass.prototype = new TempClass();
ChildClass.prototype.constructor = ChildClass;
ChildClass.prototype._superConstructor_ = ParentClass;
ChildClass.prototype._superClass_ = ParentClass.prototype;
}
Object.prototype._extends_ = function( ChildClass, ParentClass )
{
function TempClass() {}
TempClass.prototype = ParentClass.prototype;
ChildClass.prototype = new TempClass();
ChildClass.prototype.constructor = ChildClass;
ChildClass._superConstructor_ = ParentClass;
ChildClass._superClass_ = ParentClass.prototype;
};
var MyType = function()
{
var av = Array.prototype.slice.apply(arguments,[0]);
print("new MyType(",av.join(','),')');
this.prop1 = 1;
};
var MySubType = function()
{
var av = Array.prototype.slice.apply(arguments,[0]);
MySubType._superConstructor_.call( this, av );
print("new MySubType(",av.join(','),')');
this.prop2 = 2;
};
Object._extends_( MySubType, MyType );
var x = new MySubType(7,3,11);
print( x.prop1 + ":" + x.prop2 );
print( x instanceof MyType );
Output:
new MyType( 7,3,11 )
new MySubType( 7,3,11 )
1:2
true
:-?
--
----- stephan beal
http://wanderinghorse.net/home/stephan/
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