yes, i have tried it too.. ''+=any faster than [any].join('')
on simple operations any+any+any faster than [any,any,any].join('')-- Regards, Kiswono P GB -- v8-users mailing list [email protected] http://groups.google.com/group/v8-users
yes, i have tried it too.. ''+=any faster than [any].join('')
on simple operations any+any+any faster than [any,any,any].join('')-- Regards, Kiswono P GB -- v8-users mailing list [email protected] http://groups.google.com/group/v8-users