You are correct, you can remove specific versions by passing in the 
--box-version.


On Saturday, May 29, 2021 at 6:16:22 AM UTC-5 [email protected] wrote:

> On 5/29/21 3:04 AM, Alvaro Miranda Aguilera wrote:
> > Hello
> > 
> > If you are comfortable with command line, you can remove the directory 
> > version of the box you want to remove.
> > 
> > .vagrant.d/boxes/generic-VAGRANTSLASH-openbsd6/1.8.40/
> > 
> > 
>
> Well, that doesn't answer the question I asked. What I asked was:
>
> > 
> > Is the following the correct way to remove that one and
> > leave the other two untouched?
> > 
> > ###
> > vagrant box remove generic-openbsd6 --provider virtualbox --box-version
> > 1.8.40
> > ###
> > 
>
> I know that I can remove directories from the command line. But I would 
> presume that a 'vagrant' command would be so formulated as to do that 
> safely and precisely and would be knowledgeable enough so that it would 
> delete the correct information in as many places as is needed -- rather 
> than having the user attempt to guess where all the relevant data is 
> located.
>
> So I re-pose my original question.
>
> Thank you very much.
> Jim Keenan
>

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