Sam Liddicott <s...@...> writes:

> 
> The expression of an out parameter must be an LHS (left hand side) assigment.
> 
> You can try
> 
> *(condition?&inh:(inh_type*)NULL)
> 
> You'll have to fill inh_type with thr right type

Tried:
*(true?&inh:(int *)null)

Gives me an error:
error: Cannot pass value to reference or output parameter

With out modifier before:
error: ref and out method arguments can only be used with fields, parameters, 
and local variables

Without *:
error: Argument 7: Cannot convert from `int*' to `int'

And the same errors when I replace the expression by pointer variable.

I also tried nullable variable, which compiled, but does not do what I want, 
because the generated C code creates a new temporary and passes in the pointer 
to that, independent on the old value of the nullable variable.

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