If I don't include the out specifier, how will glGetActiveAttrib change
the value of name?
> Am 13.03.2010 16:32, Tristin Celestin wrote:
> > I have a OpenGL function with this declaration:
> >
> > GLAPI void APIENTRY glGetActiveAttrib (GLuint program, GLuint index,
> > GLsizei bufSize, GLsizei *length, GLint *size, GLenum *type, GLchar
> > *name);
> >
> > The parameters length, size, type, and name are all outputs of the
> > function. My question is how to deal with the name parameter. A GLchar* is
> > just a char*.
> >
> > Is this the correct way to bind the above function?
> >
> > public static void glGetActiveAttrib (GLuint program, GLuint index, GLsizei
> > bufSize, out GLsizei length, out GLint size, out GLenum type, out string
> > name);
>
> Just 'string', not 'out string', otherwise it woule be 'GLchar **'.
>
>
> Best regards,
>
> Frederik
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