I just checked it out with C# and it shows exactly the same behaviour. I expected it to do

x = 3;
y = x;

rather than

x = 3;
y = 3;

Very interesting and good to know.



I think that it is pretty consistent and expected behaviour not only in
Vala but in other languages as well (as long as they allow such things). I
would be worried if it would work other way around. Example:

int x, y;
x = 2;
y = x = 3;

I expect that both y and x will have same value, 3. I would not like to get
y=2 and x=3.

I hope that this clears things up but I also wonder in which language it
works differently.

JC

2012/11/1 foracc <for...@d00m.info>

Hello list,

I stumbled on some (for me) unexpected behaviour when setting and getting
a property at the same time, which is not consistend with simple types like
int.

When doing something like

int x = (myclass.myproperty = y);

x will be set to y, and not whatever mycalss.myproperty will be (or what
was mycalss.myproperty set to before). Is this a limitation of Vala?

The code below shows this behaviour and should be pretty self-explanatory.

---------- snip ----------

public class myclass : Object
{
    private int _number;

    public int number {
       set { _number = value * 2; }
       get { return _number; }
    }
}

public void main(string[] args)
{
    myclass m = new myclass();
    int i = 2;

    m.number = 2;

    // prints 4, ok
    stdout.printf("number: %d\n", m.number);

    // prints 3, not 6 (or at least 4)
    stdout.printf("number: %d\n", m.number = 3);

    // prints 6, ok
    stdout.printf("number: %d\n", m.number);

    / prints 5, ok
    stdout.printf("i: %d\n", i = 5);
}

---------- snip ----------
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