That is a good question actually. I mean yannick's answer works in this
overly-simplified case, but overall, is there a technical reason it doesn't
work this way?

Steven N. Oliver


On Thu, May 15, 2014 at 2:06 PM, geovanisouz...@gmail.com <
geovanisouz...@gmail.com> wrote:

> Sorry for my mistake. I used the same variable "result". Declaring:
>
>     var result = add(2, 3);
>     var result2 = add(1.2, 3.4);
> ​
> Worked fine. Thank you Yannick.
>
> But the discussion can continue.
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