Hello,
I have come across this weird closure thing. In other programming
languages, I would expect the closure in t to have a copy of i, but it
only has a reference. Is it expected?
Best regards,
Vivien
public delegate void Thunk();
public static void run (Thunk t) {
t ();
}
int main() {
int i = 0;
Thunk t = () => {
stdout.printf ("%d = 0, right?\n", i);
};
i = 1;
run (t);
return 0;
}
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