Jodi
1 TO 5........... Step is default of 1.
The critical Item here is To 5.... not to 6 or to 96. To 5....
Execution stops at 5..... Perhaps if you tried running the
following code ion the immediate window you would understand
for times = 0 to 5 step 1:debug.print times: next times
----- Original Message -----
From: "Jodi Silver" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Sunday, May 23, 2004 8:03 PM
Subject: Re: [vbhelp] Newbie needing help in loops
> I still do not understand what the final value of the IntB would be if it
is 1 to 5 and a step 1.
> Would The final value be 5 or is it one higher (6). That was the question.
>
> 1.Does it end up one or more higher when ending the loop, or is the final
count equal to the 5 if the step is 1.
>
> 2. Is 1 to 5 the same as 1 to 5 step 1
>
> Jodi
>
>
> Matt Lorenz Jr <[EMAIL PROTECTED]> wrote:
> A for / next loop is just short hand for a do loop.
>
> for times = 0 to 10 step 2
> msgbox times
> next times
>
> would give you message boxes saying 0, 2, 4, 6...
>
> times = 0
> do until times > 10
> msgbox times
> times = times + 2
> loop
>
> would give you a message boxes saying 0, 2, 4, 6 ...
>
>
> I think something you are noticing is WHERE in the for next loop the logic
> is being checked.
>
> With a do loop you can have:
>
> do until such and such
> loop
>
> or
>
> do
> loop until such and such
>
> I do see your point - your counter always ends up 1 or more higher
> (depending on your step) after it falls out of the loop.
>
> This is okay - you almost never really care what the value is when falling
> out of a for / next loop. This is because you usually have some
> predetermined number you using. For example, you know there are 100 times
> in a list box and you want to process them you would do
> For Times = 1 to 100
> 'processing statements
> Next times
>
> More likely you would do this:
>
> For times = 0 to lstItems.listcount - 1
> 'processing statements
> Next times
>
> So you see - you don't care that your times counter gets one past when you
> fall out.
>
> In general, if you are counting things up to discover the number that is
> there you use a do loop, not a for next loop. Example, how many entries
are
> in a file on the hard drive called logentries.txt
>
> open "c:\logentries.txt" for input as #1
> ctr = 0
> do until eof(1) = true
> line input #1, linefromfile
> ctr = ctr + 1
> loop
> close #1
> msgbox "There are " & ctr & " lines in the file."
>
> You can see, you could never properly process a file with unknown amounts
of
> data with a for / next loop.
>
> I hope this gives you a little clarity.
>
>
>
>
> ----- Original Message -----
> From: "jodidee2004" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Saturday, May 22, 2004 7:50 PM
> Subject: [vbhelp] Newbie needing help in loops
>
>
> > Hello,
> > I am a newbie and I need some help understanding some basic concepts.
> >
> > If I had a loop structure that read:
> > For IntNumber=1 to 10
> > and I also had
> > For IntNumber 1 to 10 step 1
> > are these identical loop statements?
> >
> > Suppose I had a for next loop like this:
> > for intB=1 to 7 Step 1
> > Print IntB
> > Next IntB
> >
> > What would the value of IntB be when the loop stops? I think it would
> > be 7 is that correct? Or is it 7 plus 1 to get 8.
> > ---------------------------------------------------------------
> > I understand that the step counts by those numbers.
> > So if I had
> > for IntCount = 4 to 10 step 2
> > Print IntCount
> > next Intcount
> >
> > the value of the numeric variable would be 12 when the loop stops.
> >
> > 4,8,10,12 and it would stop at 12 since this is higher than 10.
> >
> > Can someone explain this to me a bit better, I am confused by all
> > this. Does it increase at the end the amount of steps past the end
> > value?
> >
> > Jodi
> >
> >
> >
> >
> >
> >
> >
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