Thanks
--- In [EMAIL PROTECTED], "Tim Rupp" <[EMAIL PROTECTED]> wrote:
> Try this...it's about as simple as I can make it and it should 
point you
> in the direction.
>  
>  
> Dim Temporary As Double
> Dim Operand1 As Double
> Dim CalcInProcess As Boolean
>  
> Private Sub TextBox1_TextChanged(ByVal sender As System.Object, 
ByVal e
> As System.EventArgs) Handles TextBox1.TextChanged
>   Temporary = Val(TextBox1.Text)
> End Sub
>  
> Private Sub Button1_Click(ByVal sender As Object, ByVal e As
> System.EventArgs) Handles Button1.Click
>   If CalcInProcess = False Then      'This is the first operand 
input
>     Operand1 = Temporary
>     TextBox1.SelectionStart = 0 
>     TextBox1.Select(TextBox1.SelectionStart, TextBox1.TextLength)
>     TextBox1.Focus()
>     CalcInProcess = True
>   Else       'We will now do the addition operation
>     TextBox1.Text = Temporary + Operand1
>     TextBox1.SelectionStart = 0
>     TextBox1.Select(TextBox1.SelectionStart, TextBox1.TextLength)
>     TextBox1.Focus()
>     CalcInProcess = False
>   End If
> End Sub
>  
>  
> HTH,
> Tim
>  
>  
> 
> -----Original Message-----
> From: sramey28 [mailto:[EMAIL PROTECTED] 
> Sent: Tuesday, August 31, 2004 12:55 PM
> To: [EMAIL PROTECTED]
> Subject: [vbhelp] Re: trying to make calculator with vb.net
> 
> 
> Ok Tim I worked with what you told me. Here is my code now. I 
don't 
> understand how you are resetting the cursor back to first 
character 
> before the operator Add ect. is clicked. So then I can't assign 
that 
> number to opt2. Right now I can enter 1 number click + and then 
> enter a new number. I then click = and the answer given is the 
> second number plus itself. The first number is ignored, so the 
> second number is being assigned to opt1 and replacing the first 
> number. So the assignment of a number to (opt2) isn't happening. I 
> think there should be more to the textchange of the textbox but 
> what? 
> 
> Private Sub btnNine_Click( _
>     ByVal sender As System.Object, _
>     ByVal e As System.EventArgs) _
>     Handles btnNine.Click
>         number = number + "9"
>         txtEnter.Text = number
>     End Sub
> 
>     Private Sub btnDecimal_Click( _
>     ByVal sender As System.Object, _
>     ByVal e As System.EventArgs) _
>     Handles btnDecimal.Click
>         number = number + "."
>         txtEnter.Text = number
>     End Sub
> 
>     Public Function Addition() As Integer
>         answer = opt1 + opt2
> 
>     End Function
> 
>     Private Sub btnAdd_Click( _
>     ByVal sender As System.Object, _
>     ByVal e As System.EventArgs) _
>     Handles btnAdd.Click
>         txtEnter.Clear()
>         txtEnter.ResetText()
>         txtEnter.Text = String.Empty
> 
>         number = Nothing  'this clears the box so only the 
next      
> number I enter appears, but then I think this cancels out the 
first 
> number.
> 
>     End Sub
> 
>     Private Sub txtEnter_TextChanged( _
>     ByVal sender As Object, _
>     ByVal e As System.EventArgs) _
>     Handles txtEnter.TextChanged
>         opt1 = Val(txtEnter.Text)
>         opt2 = Val(txtEnter.Text) 'where do I put this line.
>     End Sub
> 
>     Private Sub btnEqual_Click( _
>     ByVal sender As Object, _
>     ByVal e As System.EventArgs) _
>     Handles btnEqual.Click
>         opt2 = Val(txtEnter.Text) 'does it go here 
>         Addition()
>         txtEnter.Text = CStr(answer)
>     End Sub
> 
> --- In [EMAIL PROTECTED], "sramey28" <[EMAIL PROTECTED]> wrote:
> > Thanks this should be a big help. 
> > 
> > 
> > --- In [EMAIL PROTECTED], "Tim Rupp" <[EMAIL PROTECTED]> 
wrote:
> > > Why do anything at all with number presses....let your text 
box 
> > hold the
> > > value as it is entered from the keystrokes using the 
> > TextBox.TextChanged
> > > method to gather your input number.  Perhaps you want to 
verify 
> > that the
> > > keystroke is numeric, decimal point, and perhaps A-E if your 
> going 
> > to
> > > allow hex calculations...but that's your choice. When the 
> operand 
> > key is
> > > hit (+,-,/,*) just take the value of your text display and 
> assign 
> > that
> > > to a temporary value (Operand1 = Val(txtEnter.Text) ) 
> > >  
> > > At that point I'd highlight the text in the text box and reset 
> the
> > > cursor to the first character so that the next keystroke entry 
> will
> > > clear your text box. Then assign the second operand and 
perform 
> the
> > > operation in the same manner when the equals key or successive
> > > calulation key is struck. At that point you would perform the
> > > calculation, assign the result to your result value, and 
display 
> > that
> > > value in your text box (once again highlighting the text and 
> > placing the
> > > cursor at the beginning of the field so that additional 
entries 
> > from the
> > > keyboard once again clear your display.
> > >  
> > > For even more fun, try the RPN calculator type!
> > >  
> > > Enjoy,
> > > tim
> > >  
> > > 
> > > -----Original Message-----
> > > From: sramey28 [mailto:[EMAIL PROTECTED] 
> > > Sent: Monday, August 30, 2004 4:57 PM
> > > To: [EMAIL PROTECTED]
> > > Subject: [vbhelp] trying to make calculator with vb.net
> > > 
> > > 
> > > Hi, I'm trying to learn vb.net for work. I only have books and 
> > > online class and online help to learn from. I'm trying to make 
a 
> > > simple calculator. here is some of my code. The btnNine_click 
is 
> > > just like procedures for the numbers 0-8. What I need help 
with 
> is 
> > > the idea of the Display (txtEnter) showing the right numbers. 
> > Right 
> > > now I'm only working on addition of numbers. I'm not sure if 
the 
> > > addition function has to be a function or sub. Here are the 
> steps 
> > to 
> > > my problem.
> > > 
> > > 1. any number is clicked. 
> > > 2. This number shows up in display
> > > 3. Click the (add +) button
> > > 4. previous number disappears, leaving display blank
> > > 5. Next Click another number.
> > > 6. That one appears in display
> > > 7. Now click (equal =) button
> > > 8. The answer displayed is First number plus itself.
> > > 
> > > I think my problem lies in the Addition function line:
> > > answer = Double.Parse(number) + Double.Parse(lblNum.Text)
> > > both number and lblNum.text point to the same number. 
> > > 
> > > Main question 
> > > How do I get the second number entered recongized and added to 
> the 
> > > first number entered. This easy if there are two textboxes, 
but 
> > with 
> > > one I don't know how to do this. 
> > > 
> > >     Private Sub btnNine_Click( _
> > >     ByVal sender As System.Object, _
> > >     ByVal e As System.EventArgs) Handles btnNine.Click
> > >         number = number + "9"
> > >         txtEnter.Text = number
> > >     End Sub
> > > 
> > >     Private Sub btnDecimal_Click( _
> > >     ByVal sender As System.Object, _
> > >     ByVal e As System.EventArgs) Handles btnDecimal.Click
> > >         number = number + "."
> > >         txtEnter.Text = number
> > >     End Sub
> > > 
> > >     Public Function Addition() As Integer
> > >         answer = Double.Parse(number) + Double.Parse
(lblNum.Text)
> > >         lblNum.Text = String.Empty    'cleared for 2nd number 
> > enter 
> > >         number = ""    'tried clear number variable for second 
> > number
> > >     End Function
> > > 
> > >     Private Sub btnAdd_Click( _
> > >     ByVal sender As System.Object, _
> > >     ByVal e As System.EventArgs) Handles btnAdd.Click
> > >         lblNum.Text = CStr(number)      'These two lines are 
more
> > >         txtEnter.Text = String.Empty    'of trying to clear 
the  
> > >         Addition()                      'number      
> > >     End Sub
> > > 
> > >     Private Sub btnEqual_Click( _
> > >     ByVal sender As Object, _
> > >     ByVal e As System.EventArgs) Handles btnEqual.Click
> > >         txtEnter.Text = CStr(answer)
> > >     End Sub
> > > Thanks sramey28
> > > 
> > > 
> > > 
> > > 
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