# Re: [vchkpw] Question on msg/hour graph

```Got it.. I just wanted to make sure that I was understanding what it
was.. thanks :)```
```

On Fri, 17 Sep 2004 10:34:40 -0500, Ken Jones <[EMAIL PROTECTED]> wrote:
> On Friday 17 September 2004 07:34 am, Matt Hoppes wrote:
> > Hi,
> > On the inter7 qmailmrtg7 graphs.. what exactly is the msg/hour graph
> > displaying?
> It is displaying the averaged number of messages per hour.
>
> > I know MRTG takes 5 minute averages but what exactly is
> > it averaging?
> Every 5 minutes we get an exact count of number of messages
> received in the last 5 minutes. qmailmrtg7 multiplies that value
> by 12 to change the time scale to msg/hour. That value is handed
> to mrtg which averages it with the prior data samples.
>
> > I know it's doing the messages.. but how do you do
> > msg/hour in a 5 minute average?
> messages(in 5 minutes) * 12 = msg/hour
>
> > I guess I'm missing some sort of logic there..
> Most folks find it easier to view msg/hour instead of msg/5 mins.
> Hence the multplication. Which means, if you only get 1 message
> in 5 minutes, mrtg will show 12msg/hour.
>
> Ken Jones
>
```