Re: Parser Update

[Gunnar R|nning]

"Geir Magnusson Jr." <[EMAIL PROTECTED]> writes:


> 
> 1) When a non-null reference (a reference that refers to actual data in
> the Context) is preceeded by a '\', it will be rendered as $<reference>. 
> 
> 
> #set $foo = "woogie"
> \$foo => $foo
> \$bar => $bar
> 

So what about escaping the backslash itself ? Let's say I want the
following output by accessing $foo :

"\woogie"


regards, 

        Gunnar