I recognize the problem inherant in our comparisons - however, I have to
be the wet blanket again and offer a counter-example that would result
in confusing results (to me, anyway) :
public class Test
{
public static void main( String arg[] )
{
Double left = new Double( "2.1");
Double right = new Double( "2.0");
if(( left instanceof Number) && (right instanceof Number))
{
int leftValue = ((Number)left).intValue();
int rightValue = ((Number)right).intValue();
System.out.println( "Result :" + (leftValue == rightValue));
}
}
}
you will see for the output
Result: true
when clearly they are not equal. Again, I am not suggesting there
aren't problems - however, I can offer the above example of one problem
that arises when using Number over Integer...
geir
[Snipped off patches for the bandwidth-impaired...]
--
Geir Magnusson Jr. [EMAIL PROTECTED]
System and Software Consulting
Developing for the web? See http://jakarta.apache.org/velocity/
You have a genius for suggesting things I've come a cropper with!
