Hi,
> There is this mysterious line in scalar_expression<>'s definition: > > private: > typedef typename LHS::value_type DummyType; //Visual > C++ 2005 does not allow to write LHS::value_type::value_type > > This prevents us from using a scalar expression whose LHS is a > scalar_expression. Hmm, this might be outdated thanks to the use of the traits-mechanism in the subsequent line. Just using result_of::cpu_value_type<LHS>::type for the ScalarType typedef might work. Please let me know if this is insufficient. > The comment is slightly mysterious. Is > typedef typename LHS::value_type value_type; not allowed? > I can't believe that VS would break template recursion so easily, but > perhaps I'm wrong. The original typedef for ScalarType was typedef typename LHS::value_type::value_type ScalarType; and this indeed caused the compilation to fail on VS 2005. The error wasn't reproducible in a super-simple context, so some more complex interaction was necessary to cause this. With the traits-stuff things should work, just give it a try. Maybe you have to add one or two additional overloads for result_of::cpu_value_type Best regards, Karli ------------------------------------------------------------------------------ Learn Graph Databases - Download FREE O'Reilly Book "Graph Databases" is the definitive new guide to graph databases and their applications. Written by three acclaimed leaders in the field, this first edition is now available. Download your free book today! http://p.sf.net/sfu/NeoTech _______________________________________________ ViennaCL-devel mailing list ViennaCL-devel@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/viennacl-devel
