kyanh wrote:
* tru+o+'c khi cha.y child_process: resource chie^'m bo+?i winefish la` 0%
* khi cha.y child_process: winefish chie^'m 0%, child chie^'m khoa?ng 30% ta`i
nguyene
* sau khi child_process ke^'t thu'c (kho^ng bie^'t ke^' thu'c kie^?u gi`),
winefish chie^'m 30% ta`i nguye^n <=== lo^~i.
Y' cu?a em la`: ta`i nguye^n cu?a tie^'n tri`nh con ddu+o+.c gia?i pho'ng
the^' na`o, trong hai tru+o+`ng ho+.p:
* tie^'n tri`nh con thoa't bi`nh thu+o+`ng?
* tie^'n tri`nh con bi. gu+?i signal SIGTERM?
Theo mi`nh thi` hoa.t ddo^.ng cu?a tie^'n tri`nh con (chi? la` shell)
kho^ng a?nh hu+o+?ng gi` dde^'n tie^'n tri`nh cha, vi` ddo' la` hai
chu+o+ng tri`nh ddo^.c la^.p. Cho ne^n vie^.c resource (theo mi`nh
hie^?u o+? dda^y la` cpu usage) ta(ng dde^'n 30% co' le~ la` do tie^'n
tri`nh cha\.
Chu+o+ng tri`nh cu?a Ky` Anh se~ co' da.ng nhu+ sau:
........
1.Thi mo^.t so^' le^.nh A
2.Ta.o tie^'n tri`nh con
3.Thi ha`nh mo^.t so^' le^.nh B
4.Cho+` tie^'n tri`nh con thoa't
5.Thi ha`nh mo^.t so^' le^.nh C
.....
Theo nhu+ Ky` Anh khi chu+o+ng tri`nh dde^'n 5, CPU se~ ta(ng 30%
Ba^y gio+` Ky` Anh thu+? debug theo hu+o+'ng sau:
Comment 2 va` 4, tu+'c la` kho^ng ta.o tie^'n tri`nh con va` cho+`
tie^'n tri`nh con thoa't, sau ddo' cha.y la.i chu+o+ng tri`nh, xem thu+?
dde^'n le^.nh 5 thi` CPU co' co`n ta(ng nu+~a hay kho^ng?
Ho?i the^m mo^.t chu't, Ky` Anh ta.o bao nhie^u tie^'n tri`nh con va^.y\?
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