Zdenek Sekera wrote:
I have this:
if (char =~ '\m[;|<>?:[EMAIL PROTECTED]&*(){}\\_+-[\]/\"]')
do something
endif
Basically it is checking for all non-alphanumeric chars
(expect '=').
1. how do I include the "'" char?.
I can't seem to find a proper way.
(I'd like to keep the patter in enclosed in '...')
2. why when the pattern ends with '+' or '\+' do I get
an error?
---Zdenek
1. Starting with version 7, you can have a single quote in a
single-quoted string by doubling the single quote. Thus, '''' (four
single quotes) represents one single quote and 'a''b' (quote a quote
quote b quote) is a string consisting of the letters a and b with a
single quote between them.
In all versions, you can concatenate strings, and a single quote can be
enclosed in a double-quoted string. Thus, '"' . "'" (single double
single space dot space double single double) is an expression whose
value is a String consisting of a double quote followed by a single quote.
2. I don't know, but I think it's either a bug, or documented under
":help pattern.txt" somewhere.
Best regards,
Tony.
