On Sat 5-Aug-06 10:42pm -0600, A.J.Mechelynck wrote:
> Bill McCarthy wrote:
>> Example 1:
>>
>> :echo "<" . matchstr(" 1.2345 ","[0-9.]") . ">"<CR>
>> <1>
>>
>> Example 2:
>> :echo "<" . matchstr(" 1.2345 ","[0-9.]*") . ">"<CR>
>> <>
>>
>> Why isn't the second exampe returning <1.2345>?
>>
>> Is there a better way of stripping spaces off a string?
> What you get is the first (leftmost) substring matching the pattern.
>
> In the first case the pattern matches exactly one dot or digit, and it
> matches the 1 at position 2.
>
> In the second case the pattern matches zero or more dots and digits, and
> it matches the null string at position 0.
That makes sense.
> If you had specified \+ as multi instead of * you would (IIUC) have got
> what you wanted.
I had:
Example 3:
:echo "<" . matchstr(" 1.2345 ","[0-9.]\+") . ">"<CR>
<>
Example 4:
:echo "<" . matchstr(" 1.2345 ","\s*\zs[0-9.]\+") . ">"<CR>
<>
Why did both of those fail?
> To "strip spaces off a string" I would have used substitute(string, " ",
> "", g)
That's much better:
:echo "<".substitute(" 1.2345 "," ","","g").">"<CR>
<1.2345>
Thanks Tony!
--
Best regards,
Bill
