Wrapping by substitution

[Steve Hall]

I'm having a mental block, how can I wrap a string via substitute() ?
I've been trying something like:

  let str = "123456789012345678901234567890"
  let str = substitute(str, '\n\([[:print:]]\{-10,}\)', '\n\1\n', '')
  echo str

to produce:

  1234567890
  1234567890
  1234567890


-- 
Steve Hall  [ digitect dancingpaper com ]