Hello Vim List,
I appear to be a little confused about strings "\\" vs
"\\\\" and literals '\' vs '\\'.
Here's an example.
let a = 'a\b'
echo a
This displays "a\b" (without the double quotes).
let a = "a\\b"
echo a
This displays the same thing as expected.
Also note that:
echo '\\'
echo "\\\\"
both display "\\" (without the double quotes) as expected.
But now look at these four:
echo substitute(a,'\','/','')
echo substitute(a,'\\','/','')
echo substitute(a,"\\",'/','')
echo substitute(a,"\\\\",'/','')
I expected the first and third to display "a/b" (without the
double quotes) and the second and fourth to display the
original value of the variable `a`.
They all make the substitution, even though the second and
fourth do not appear to match the variable.
Why?
--
Best regards,
Bill
