Re: replace with a number sequence

[Luke Vanderfluit]

Hi.

Tim Chase wrote:

I have these lines,
      UniqueID2       = lview.focusedItem.subItems.opIndex(0).text;
      Parent          = lview.focusedItem.subItems.opIndex(0).text;
      Children        = lview.focusedItem.subItems.opIndex(0).text;
      login           = lview.focusedItem.subItems.opIndex(1).text;
      txtCust.text    = lview.focusedItem.subItems.opIndex(2).text;
      txtProj.text    = lview.focusedItem.subItems.opIndex(3).text;
      txtbDate.text   = lview.focusedItem.subItems.opIndex(4).text;
      txtdDate.text   = lview.focusedItem.subItems.opIndex(5).text;
      txteDate.text   = lview.focusedItem.subItems.opIndex(6).text;
      txtPM.text      = lview.focusedItem.subItems.opIndex(7).text;
      txtLang.text    = lview.focusedItem.subItems.opIndex(8).text;
      txtVendor.text  = lview.focusedItem.subItems.opIndex(9).text;
      txtInvoice.text = lview.focusedItem.subItems.opIndex(10).text;
      txtPMFund.text  = lview.focusedItem.subItems.opIndex(11).text;
      txtProjFund.text= lview.focusedItem.subItems.opIndex(12).text;
      txtA_No.text    = lview.focusedItem.subItems.opIndex(13).text;
      txtNotes.text   = lview.focusedItem.subItems.opIndex(14).text;
      txtStatus.text  = lview.focusedItem.subItems.opIndex(15).text;

and I would like to replace the number between the parens () to a sequential number starting from 0. ie,

If you highlight the lines in question and issue the following:

        :'<,'>s/opIndex(\zs\d\+\ze)/\=line('.')-line("'<")

It should renumber them starting at zero for you.

I'd be glad to explain what that's doing if you have trouble
un-opaquifying it :)

I've used the line function in the past. And it's something seems to
recur frequently.
Since I'm always learning new things in vim, I'd appreciate any
instructive comment on your solution. The use of zs and ze is also
interesting (-:

Kind regards.
Luke.

-tim

--
Luke Vanderfluit
Analyst / Web Programmer
e3Learning.com.au
08 8221 6422