"Tim Chase" wrote,
Using a simple change to Tim Chase' original substitution response, you
have:
[snip]
if you don't want to type it in every time,
:vmap <C-I> :s/\d\+/\=line('.')-line("'<")<CR>
which adds ctrl-i as a key in visual mode to do the job.
Ok, one last question on this. :-)
Is there a way to start this from where the cursor is and end with the
first
non-matched instance? For example,
char[] str = null;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
int i = 0;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
bla.blah.blahh[0].text;
So, if the cursor is on the first bla.* the first 6 lines will be
numbered
sequentially and stop there. Is this possible?
Well, if you have the above mapping, you can then map
:nmap <f4> vip<c-i>
which will visualize the block in question and then reduce the problem to
the previously solved problem.
If you plan to then expand this to auto-numbering blocks throughout your
your document, you might try something like (broken into multiple lines
for easy reading, but would be all one mappable line)
:g/bla\.blah\.blahh\[\d/if getline(line('.')-1)=~'blah\.blah\.blahh\['
| let counter = 0
| endif
| s/blahh\[\zs\d\+/\=counter/
| let counter = counter + 1
I haven't tested it (so there's likely some escaping I got wrong), but it
should do similar to my previous mapping, only when the previous line
doesn't match the target pattern, it resets the counter to zero. It might
be reducable to something like
:g/.../if getline(line('.')-1) =~ @/
which might be a little easier to read/understand, as it uses the search
register.
Just a few ideas.
Thanks. vim rocks!
f4<CR>
What a beautiful world is this we live on!
thanks,
josé
