On Dec 30, 9:56 pm, Bill McCarthy <[EMAIL PROTECTED]> wrote:
>
> I'm not sure this is related but:
>
> :1s/\%(g\n\)\@<=1//
>
> produces:
>
> E486: Pattern not found: \%(g\n\)\@<=1
No, thats ok, because the pattern after the '\@<='
, which is '1', is tried first. Since there is no match
in the 1st line you get an error.
This is documented at ':h \@<='.
-ap
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