What about the following new binary operator?
expr-a in expr-b
The result would be boolean (i.e. integer with value 0 or 1).
If expr-b is a List, then the result is 1 if there is a list item equal
to expr-a, otherwise 0. This is equivalent (but IMHO more "readable")
than the expression
index(expr-b, expr-a) != -1
If expr-b is a Dictionary the result is 1 if there is a key equal to
expr-a otherwise 0. IMHO more readable (and less cumbersome) than the
equivalent
get(expr-b, expr-a) != 0 || get(expr-b, expr-a, 1) != 1
or the rv variable returned by
:try
: let value = expr-b[expr-a]
: let rv = 1
:catch /^Vim(let):E71[36]:/ " empty key, or key not in dict
: let rv = 0
:endtry
If expr-b is neither a List nor a Dictionary, trigger an error Ennn with
some appropriate nnn.
There is no ambiguity after the :for command since the first operand
"var" of
:for var in list
must be a variable name, not an expression containing an operator, and
the second operator "list" must be a List, not a Number.
This makes me think: what about:
:for {var1}:{var2} in {dictionary}
: ...
:endfo[r]
The loop would be executed once for every key:value pair, with {var1}
set to the key and {var2} to the corresponding value.
Advantage: less cumbersome than the equivalent
:for var1 in keys(dictionary)
: let var2 = dictionary[var1]
: ...
:endfor
As you can see, neither one of these RFEs are very important since there
already are workarounds; but they might improve readability, in a manner
analogous to the already existing (new in Vim 7)
:for i in range(var1, var2)
: ...
:endfor
compared to the equivalent (and more backward-compatible but also more
bulky)
:let i = var1
:let step = 2 * (var1 < var2) - 1 " +1 (yes), -1 (no)
:while ((var2 - i) / step) >= 0
: ...
: let i = i + step
:endwhile
:unlet i step
Best regards,
Tony.
--
We're only in it for the volume.
-- Black Sabbath
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