Try the following code:
let d={'0d': 1}
if 0 && (d.0d)
endif
. This code is completely correct if you replace `if 0` with `if 1`, but with
`if 0` it throws
Error detected while processing /home/zyx/tmp/vim/subscript-bug.vim:
line 2:
E110: Missing ')'
E15: Invalid expression: 0 && (d.0d)
. Reason is the following: when `evaluate` argument is set to FALSE in eval7()
handle_subscript does not take .0d as dictionary key (because it checks for
variable type which is VAR_UNKNOWN if evaluate is FALSE). Thus `.0d` is handled
in eval5() like string concatenation and when it tries to evaluate second
argument “0d” in eval7() it is handled like number in that big switch(**arg)
statement. As a number it can consume only leading zero, which means when
eval7() *that is handling top “(d.0d)” expression* sees that in place of
getting **arg equal to ')' it gets **arg equal to 'd' and errors out.
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