Here is a small example to illustrate the issue:

    echo 123456789 | vim - +":omap a0 :<C-U>execute 'norm 0v'.v:count1.'lh'<CR>"

This invocation puts the string "123456789" into a new buffer and creates an
operator-pending mapping `a0` that selects the first characters of the current
line for the pending operator.

Executing `3da0` deletes the first three characters of the line, leaving us
with the following buffer contents:

    456789

Repeating that last command with `.` should now delete the first three
characters again, leading to this:

    expected: 789

Instead the count seems to be reset to 1, leading to this:

    obtained: 56789

For comparison: Repeating `3x` with `.` deletes another three characters, 
instead of just one. This seems inconsistent.

-- 
-- 
You received this message from the "vim_dev" maillist.
Do not top-post! Type your reply below the text you are replying to.
For more information, visit http://www.vim.org/maillist.php

--- 
You received this message because you are subscribed to the Google Groups 
"vim_dev" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to [email protected].
For more options, visit https://groups.google.com/groups/opt_out.

Raspunde prin e-mail lui